Hi, I have a transformer question here (it's merely a practice question) that I'm a bit stuck on.
The question is in the attached image with all stated values.
My attempt:
Np/Ns=a:
\( I_{s(rated)} = \frac{V_2}{R_L} = \frac{110}{10} = 11A\)
\( E = aV_2+\frac{I_s}{a} (R_sa^2 + jX_sa^2) = a[V_s + I_s(R_s + jX_s)]\)
\( =\frac{23}{11}[110+11(0.1+j0.6)] = 232.3+j13.8V\)
\(If: I_p = I_0 + I'_s \), \(where: I'_s = \frac{I_{s(rated)}}{a}\) and \( I_0 = \frac{E}{R_0} + \frac{E}{jX_0}\)
\( then:I_p = \frac{11}{23/11} +\frac{232.3+j13.8}{1000+j0} + \frac{232.3+j13.8}{0+j1200}\)
\( I_p = 5.5j0.18 A \) or \( 5.5 \angle 1.9^o\)
The only thing is, my leturer has a similar question in the notes and has attempted the question in a totally different way using lot's of rearranging equations and such. I tried doing it his way but the answer I get does not seem to make sense. Is my above attempt correct?
The question is in the attached image with all stated values.
My attempt:
Np/Ns=a:
\( I_{s(rated)} = \frac{V_2}{R_L} = \frac{110}{10} = 11A\)
\( E = aV_2+\frac{I_s}{a} (R_sa^2 + jX_sa^2) = a[V_s + I_s(R_s + jX_s)]\)
\( =\frac{23}{11}[110+11(0.1+j0.6)] = 232.3+j13.8V\)
\(If: I_p = I_0 + I'_s \), \(where: I'_s = \frac{I_{s(rated)}}{a}\) and \( I_0 = \frac{E}{R_0} + \frac{E}{jX_0}\)
\( then:I_p = \frac{11}{23/11} +\frac{232.3+j13.8}{1000+j0} + \frac{232.3+j13.8}{0+j1200}\)
\( I_p = 5.5j0.18 A \) or \( 5.5 \angle 1.9^o\)
The only thing is, my leturer has a similar question in the notes and has attempted the question in a totally different way using lot's of rearranging equations and such. I tried doing it his way but the answer I get does not seem to make sense. Is my above attempt correct?
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