Curren to Voltage Converter at DAC's output

Thread Starter

Rayan145

Joined Feb 21, 2019
6
Hello everybody!

I am currently working on making my own Multichannel AWG. Since the DAC I picked ( AD5547) outputs current, I am designing a simple current to voltage converter at the output. I want my voltage output swing to be +- 5 V . I have included a picture of my multisim simulation below. The output current of my DAC is 2mA and I know that with the feedback used in my design : Vout = 2mA * Rf so Rf = 2500 Ohms . Other than that I just have a couple of decoupling capacitors and a compensating capacitor in parallel with Rf. Also, for simplicity, I am just using one of my DAC's output. The output voltage that I get is not what I'm expecting. I have included my design below. Any help is appreciated.

Capture.PNG

Thanks.
 

crutschow

Joined Mar 14, 2008
38,503
A 50Ω load is low.
Can that op amp drive such a low resistance load?
A typical op amp load is no lower than 1k-2kΩ.

If you want a bipolar output, this is the circuit you should use:

upload_2019-3-23_17-9-28.png
 

Thread Starter

Rayan145

Joined Feb 21, 2019
6
Hello sir!
Thanks for the quick reply. I think you're right I will bump up my load resistance .
Also, I've looked at that schematic before but I don't quite understand the top portion of the design : why do they have -VREF going to the input of the DAC ?
 

Thread Starter

Rayan145

Joined Feb 21, 2019
6
Oh, I think I understand! I do want a bipolar output. I'll try to find a way to simulate that on multisim. I'll keep you updated.

Thanks again!
 

MisterBill2

Joined Jan 23, 2018
27,502
Pardon my lack of familiarity with acronyms, but what sort of thing is an "AWG"?? I see one circuit with a D/A converter and an opamp, and other circuits with an opamp. so that leaves me a bit puzzled.
 

MisterBill2

Joined Jan 23, 2018
27,502
OK, that makes sense. Probably adding an adder arrangement could also produce a direct digital frequency Synthesizer . (DDS) The circuit does look reasonable, the challenge is always driving the low impedance load. Often that task is done with a pair of transistors in a complementary arrangement, which provides an additional benefit of being both easier and cheaper to replace in the event that the output stage is damaged by something that should not be connected.
 
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