Using parallel circuit rules and Q,V,and C relationships, prove that Ct=C1+C2 for parallel capacitors.

need at least a paragraph for an answer!

 

Maybe change the topic?

 

bujak18,

need at least a paragraph for an answer!

No you don't. C1*V + C2*V = Q1 + Q2 = V(C1 + C2) . Ct = (Q1 + Q2)/V = C1+C2 .

Ratch

 

Here is a link to a very simple walk through the proof.

hgmjr

 

Both replys from hgmjr's link & Ratch are good,if it will help I'll add some words. Prove the sum of individual caps. in parallel = to a single cap. C. As a given charge[Q] =CV, using two caps. C1 & C2 the charge on each is Q1=C1*V , Q2= C2*V, Q= Q1+Q2 or C1*V+ C2*V=CV; as caps are in parallel then all V's are the same, dividing by V gives: C1+C2=C