# Counter IC circuit needed to divide by 430khz to 1?

#### Barnett54

Joined Aug 18, 2023
5
To divide a frequency of 430 kHz down to 1, you would need a counter circuit that divides the input frequency by 430,000. This can be achieved using a programmable counter IC or by cascading multiple counter ICs to achieve the desired division ratio.

#### Ian0

Joined Aug 7, 2020
10,277
To divide a frequency of 430 kHz down to 1, you would need a counter circuit that divides the input frequency by 430,000. This can be achieved using a programmable counter IC or by cascading multiple counter ICs to achieve the desired division ratio.
You don’t say! As if no-one had mentioned that fact in the previous 20 posts.

#### ElectricSpidey

Joined Dec 2, 2017
2,889
Please don't feed the chat bots.

#### Zain_Ibrar

Joined Apr 17, 2024
1
To divide a 430 kHz signal down to 1 Hz, you'll need a counter circuit with a very high division ratio. You can achieve this using a programmable counter IC like the CD4040, which is a 12-stage binary ripple counter. Here's how you could configure it:

1. **Frequency Division**:
- The CD4040 can divide by $$2^{12} = 4096$$.
- To reach 1 Hz from 430 kHz, you'll need to divide by $$430,000 / 1 = 430,000$$.
- Since 430,000 is not a power of 2, you'll need additional circuitry to achieve this division ratio.

- To achieve the desired division ratio, you can cascade multiple CD4040 counters together.
- Connect the output of one CD4040 to the clock input ($$CP$$) of the next CD4040.
- By cascading multiple counters, you can effectively increase the division ratio.

3. **Calculation**:
- To find out how many CD4040 counters you need, divide 430,000 by 4096.
- $$\text{Number of CD4040s} = \frac{430,000}{4096} \approx 105.26$$
- Since you can't have a fraction of a counter, you'd round up to the nearest whole number.
- So, you'll need at least 106 CD4040 counters cascaded together to achieve the desired division ratio.

This setup would be quite complex and might not be practical due to the large number of ICs required. Depending on your specific application, you might want to explore alternative solutions or approaches.

#### BobTPH

Joined Jun 5, 2013
9,292
So, you'll need at least 106 CD4040 counters
Not too bad, only off by a factor of 53.

#### crutschow

Joined Mar 14, 2008
34,845
Deja vu all over again.

#### Barnett54

Joined Aug 18, 2023
5
Connect the output pin that corresponds to the desired division ratio.
Since you want to divide by 430 kHz to 1, you would connect the output pin corresponding to the 14th stage (Q14) of the CD4020B.

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#### BobTPH

Joined Jun 5, 2013
9,292
Connect the output pin that corresponds to the desired division ratio.
Since you want to divide by 430 kHz to 1, you would connect the output pin corresponding to the 14th stage (Q14) of the CD4020B.
Really? Can you show the math on that?

#### MisterBill2

Joined Jan 23, 2018
19,466
How about a string of only THREE CD4017's, that will take the 430,000 Hz down to 430 Hz. The ONE cd4020 binary counter decoded to output every 430 input pulses. But do it right and only divide by 215, then clock a "D" flipflop so you will have a nice square wave.

#### MisterBill2

Joined Jan 23, 2018
19,466
Make that a CD4521. A 4040 only has 12 stages, which would give a 105Hz output.
That 105Hz output can then clock another binary divider aitb an AND triggering from the 32 bit and the 64 bit, delivering an output every 96 pulses, which with the source frequency being 105 Hz should be very close to 1 Hz.