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I have an induction motor with a voltage of 120 at 0degrees, and current of 1 amp at -30 degrees relative.
Finding the complex power:
P = VI * cos(angle(voltage) - angle(current)
P = 120 * 1 * cos(0 - (-30))
P = 120*cos(30)
Correct?
Therefore Q will be:
Q = VI*sin(0 -(-30))
Which will give me a positive P and a positive Q. If this were a capacitive load, I would have a negative Q, correct?
Finding the complex power:
P = VI * cos(angle(voltage) - angle(current)
P = 120 * 1 * cos(0 - (-30))
P = 120*cos(30)
Correct?
Therefore Q will be:
Q = VI*sin(0 -(-30))
Which will give me a positive P and a positive Q. If this were a capacitive load, I would have a negative Q, correct?
