hi, whats the solution to \sqrt[3]{2+i11}? help is greatly appreciated. thank u.
S Thread Starter stupid Joined Oct 18, 2009 81 Dec 12, 2010 #1 hi, whats the solution to \(\sqrt[3]{2+i11}\)? help is greatly appreciated. thank u.
Georacer Joined Nov 25, 2009 5,182 Dec 12, 2010 #2 Is that a homework question? Care to post the whole of the question?
S Thread Starter stupid Joined Oct 18, 2009 81 Dec 12, 2010 #3 ±hi georacer, its not homework but m doing self study on basic maths related to signals & systems. the eq is \(^{x^3-15x-4=0}\) then x=\(\sqrt[3]{2+\sqrt{-121}}\)+\(\sqrt[3]{2-\sqrt{-121}}\) (2±i)\(^{3}\)=2±i11=2±\(\sqrt{-121}}\) x=(2+i)+(2-i)=4 i m wondering what method to arrive at the last stage. hope someone shed lite on that. thanks Georacer said: Is that a homework question? Care to post the whole of the question? Click to expand... Last edited: Dec 12, 2010
±hi georacer, its not homework but m doing self study on basic maths related to signals & systems. the eq is \(^{x^3-15x-4=0}\) then x=\(\sqrt[3]{2+\sqrt{-121}}\)+\(\sqrt[3]{2-\sqrt{-121}}\) (2±i)\(^{3}\)=2±i11=2±\(\sqrt{-121}}\) x=(2+i)+(2-i)=4 i m wondering what method to arrive at the last stage. hope someone shed lite on that. thanks Georacer said: Is that a homework question? Care to post the whole of the question? Click to expand...
Georacer Joined Nov 25, 2009 5,182 Dec 12, 2010 #4 Check this out: http://www.suitcaseofdreams.net/Roots_complex.htm I found it very useful. From a quick google search I did, I saw that this is the most popular formula.
Check this out: http://www.suitcaseofdreams.net/Roots_complex.htm I found it very useful. From a quick google search I did, I saw that this is the most popular formula.