Hey, I ran into this problem in a textbook that seems to be giving more trouble than it should be. I've tried doing it a few times, but I can't seem to get the right answer with my method. Here's the question
I tried solving it with KVL, but my answers weren't right. Here's my basic working. Can someone show me what I'm doing wrong?
First loop, clockwise.
Second Loop, clockwise
[tex]10000(I_1-I_2)+22000I_2 + 6 = 0
\newline
10000I_1 +12000I_2 = -6
\newline
10000(\frac{10+10000I_1}{25000})+12000I_2 = -6
\newline
4+4000I_2 + 12000I_2 = -6
\newline
I_2 = -10/16000 A
\newline
\therefore
I_1 = \frac{10+10000*\frac{-10}{16000}}{25000} = 0.15*10^{-3} A
\newline
\therefore I = I_1-I_2 = 0.775*10^{-3} A[/tex]
I apologise if I've made some really obvious mistakes. I feel like my approch makes less sense each time I try. Thanks for the help
I tried solving it with KVL, but my answers weren't right. Here's my basic working. Can someone show me what I'm doing wrong?
First loop, clockwise.
Second Loop, clockwise
[tex]10000(I_1-I_2)+22000I_2 + 6 = 0
\newline
10000I_1 +12000I_2 = -6
\newline
10000(\frac{10+10000I_1}{25000})+12000I_2 = -6
\newline
4+4000I_2 + 12000I_2 = -6
\newline
I_2 = -10/16000 A
\newline
\therefore
I_1 = \frac{10+10000*\frac{-10}{16000}}{25000} = 0.15*10^{-3} A
\newline
\therefore I = I_1-I_2 = 0.775*10^{-3} A[/tex]
I apologise if I've made some really obvious mistakes. I feel like my approch makes less sense each time I try. Thanks for the help
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