Charging/Discharging Capacitors

Thread Starter

8-bit

Joined Jan 7, 2014
27
I'm trying to figure out how I can have a capacitor charge and discharge in a simple circuit automatically and continually. Can somebody help. Thanks. :)
 

Thread Starter

8-bit

Joined Jan 7, 2014
27
Its not really a project, I'm just playing around with components and trying to figure stuff out. The circuit is powered by a 9v battery.

I understand the capacitor will charge until it cannot charge anymore and also that it will only discharge when the current removed from it. I am trying to figure out how to achieve this.


Thanks for the reply.
 
Last edited:

ericgibbs

Joined Jan 29, 2010
21,641
Its not really a project, I'm just playing around with components and trying to figure stuff out. The circuit is powered by a 9v battery.

I understand the capacitor will charge until it cannot charge anymore and also that it will only discharge when the current removed from it. I am trying to figure out how to achieve this.
Thanks for the reply.
Connect one end a resistor from the +V of the 9V battery and the other end to the +V terminal of the capacitor [assumed polarised capacitor].

Connect the -V of the battery to the -V of the capacitor.

As soon as you complete the connections the capacitor voltage will rise exponentially. A DVM across the capacitor terminal will show this rise.
It will fully charged to close to 9V in 5 Time Constants.

When fully charged, disconnect the battery from the circuit and connect the free end of the resistor to the -V of the capacitor, the cap will discharge thru the resistor,, measure the Vcap with your DVM.

Use this link.
http://hyperphysics.phy-astr.gsu.edu/hbase/electric/capdis.html
E
 

wayneh

Joined Sep 9, 2010
18,183
You might like to look up the "Blinky" circuit. It alternates flashing two LEDs and the timing is accomplished by charging and discharging capacitors. Fun and instructive project.
 

BobTPH

Joined Jun 5, 2013
11,677
Or an NE555 in the astable configuration. It works by alternately charging an discharging a capacitor, and the way it does so would be quite instructive.

Bob
 
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