Charge measurement.

Thread Starter

Sourc3

Joined Dec 2, 2021
81
Hi everyone, (sorry for my english)
Im trying to characterize 2 amplifier in serie. For that, some mate explain me that I need to calculate the charge of a pulse in the input and in the output.
At the input of the signal, there are a voltage divider and a condenser that I should subtract. The conectivity is like a picture I will upload.
We think that the integer of the signal in the scope divide by Rscope, is the charge of the pulse, We divide behind 2 and subtract the condenser but we dont know to calculate the charge of the condenser. Later We divide the charge of the output signal for input signal and that should be the GAIN?
I wait you can help me and thanks in avance.
Best regards.
charge.pngTest_circuit.JPG
 

Thread Starter

Sourc3

Joined Dec 2, 2021
81
But my friend said that is ChargeOUT/ChargeIN, in the Vtest of diagram you can see a capacitor that destroy my pulse.
He said:
ChargeIN = Vpp(Pulse)*0.2(tensor divider)*capacitor
ChargeOUT = Interger of the scope area / Rscope
GAIN = ChargeOUT/ChargeIN.
Do u think is wrong?
Regards.
 

Thread Starter

Sourc3

Joined Dec 2, 2021
81
But my friend said that is ChargeOUT/ChargeIN, in the Vtest of diagram you can see a capacitor that destroy my pulse.
He said:
ChargeIN = Vpp(Pulse)*0.2(tensor divider)*capacitor
ChargeOUT = Interger of the scope area / Rscope
GAIN = ChargeOUT/ChargeIN.
Do u think is wrong?
Regards.
Charge is the wrong tern. I think you mean voltage. Gain is voltage out divided by voltage in.

Bob
Im waiting values around GAIN = 600 and and using 1MOhm for Rscope, I get values around GAIN = 0,053.
 
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