How much charge is in the capacitor a long time after the switch is closed?

 

Welcome to AAC!

For homework, you need to show your work.

 

If you don't know enough to show some work, then explain what you know about the following questions:

What does it mean for it to be "a long time" after the switch has closed?

What determines that it's been long enough?

How much current is flowing into the capacitor once this "long time" has passed?

Answer those (or show your best attempt) and we'll proceed from there.

 

Q = C x V

What is the final value of V (epsilon in this case) ?

Regards, Dana.

 

Q = C x V

What is the final value of V (epsilon in this case) ?

Regards, Dana.

By "epsilon" do you mean "E" (the battery voltage, written as a script uppercase E)?

If so, then look again.

 

Looked like -

https://en.wikipedia.org/wiki/Epsilon

Regards, Dana.

 

A capital E, either print or script, is often used for a voltage (coming from "electromotive force").

 

Looked like -

https://en.wikipedia.org/wiki/Epsilon

Regards, Dana.

Yup, and look again as @WBahn has clued. The steady state voltage on C is not E.