Dear all
I have a CBB written on it the following code can any one help me with its size to replace it

21F - up
633j - down

thanx

 

633J

1. Capacitance = 633 = 63 + 3Zeros = 63.000pF = 63nF
2. Tolerance = J = 5%

21F, I´m not sure, but it's relative to the voltage

 

633J

1. Capacitance = 633 = 63 + 3Zeros = 63.000pF = 63nF
2. Tolerance = J = 5%

21F, I´m not sure, but it's relative to the voltage

Thanks for your help but I got another circuit with number 683l
This circuit is for florescent lamp "car angel eye light"

 

First capacitor is likely the same as second, 683J not 633J.

 

First capacitor is likely the same as second, 683J not 633J.

I think it's correct 633 and the second is 683

Any idea how to figure out the capacitor capacity

 

Why do you think 633 is the correct marking?
63nF is not a standard value. Nobody makes it.

 

Why do you think 633 is the correct marking?
63nF is not a standard value. Nobody makes it.

That's what am talking about
What about the following :

Capacitance = 21 = 2 + 1 Zero = 20pF

 

Look at the marking carefully.
The middle numeral is a scratched 8 so that it appears like 3. The scratch extends to the bottom of the 6.
It is 683 = 68nF

 

Look at the marking carefully.
The middle numeral is a scratched 8 so that it appears like 3. The scratch extends to the bottom of the 6.
It is 683 = 68nF

Thanks am going to try it.