Capacitive Decoupling of IC's

Thread Starter

PauloConstantino

Joined Jun 23, 2016
266
Hi all,

may I ask you a question please?

I am building a large circuit on breadboards, with lots of IC's. And I am wondering what is the best way to decouple each IC from the power supply ?

I have added one 100nF capacitor per IC, but the way I attached these capacitors is as follows, each capacitor has one leg as close as possible to Vdd of each IC, however the other leg is far away from the GND of the IC's. That's because I am putting the capacitors directly at the power rails from rail to rail.

Does this work? Also i have thought of adding one extra capacitor per IC, connected the same way as above but close to the GND of each IC rather than Vdd.

Should the capacitors be connected in a different way? Should them be with one leg at Vdd and the other at GND directly? Like above the IC. This makes the legs rather long which is of concern,,,

Please help...

Thank you !
 

dl324

Joined Mar 30, 2015
18,329
One decoupling cap per power lead on each IC is the most conservative design. If you don't have ground or power planes, you can't avoid long leads. I'd do as you're doing.

Most guidelines will also have you add some electrolytic caps for better low frequency decoupling.
 

Veracohr

Joined Jan 3, 2011
783
as you are building it on a breadboard, you cannot be working on super-high frequencies or high current levels. I wouldn't worry too much about it.
I've had high frequency noise problems on breadboards that were solved by decoupling even when my signals were audio frequencies.
 

crutschow

Joined Mar 14, 2008
38,512
each capacitor has one leg as close as possible to Vdd of each IC, however the other leg is far away from the GND of the IC's. That's because I am putting the capacitors directly at the power rails from rail to rail.
Doesn't the ground rail go close to the ground pins on the IC's?
It should.
 
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