O/P current equation for current amplifier using op amp in non inverting mode.

 

Sorry, the purpose of the forum is not to replace Google.

Bob

 

O/P current equation for current amplifier using op amp in non inverting mode.

Have you any specific question?

 

Have you any specific question?

yes I have to derive output current equation

 

Hi ARE,
As this is homework, you must post your best attempt at answering, we can then help you.
E

 

Them we would need a specific circuit, wouldn’t we? And it sounds like this is homework. Is it?

Bob

 

And it sounds like this is homework. Is it?

I'm really suspicious about that too. Especially since it is posted here...

 

yes I have to derive output current equation

Then show us the circuit you're working with and your best effort to solve it.

"Can someone help me" isn't a very good title for a thread.

 

https://www.analog.com/media/en/training-seminars/tutorials/MT-034.pdf ?Pg.4 (below the Fig.4)

 

O/P current equation for current amplifier using op amp in non inverting mode.

For a quick idea what you have to do without having a circuit to see, usually you have to sum the currents going into the inverting input terminal. The input currents have to sum to zero. This is when the non inverting terminal is grounded which covers a lot of circuits.
See if that helps, but it would be better if you posted a circuit and tried to solve this yourself first.

It's a little different for a current mode op amp though. Then you have to sum the currents going into both inputs, more or less. You may end up doing this for a voltage mode op amp also if the non inverting terminal is not grounded.

These differences show us that we at least need to know what kind of op amp it is, and a circuit would allow us to perform the correct analysis.

These op amps would serve as prototypes for this kind of problem:
LM358 (voltage mode)
LM3900 (current mode)

I hope i remembered those part numbers correctly

BTW there are also specialized types of op amps that do not fit in those categories they have a dedicated purpose that only the data sheet could tell us about. So you can see the importance of telling us more about this question.

 

He is not only too lazy to do his own homework, he is too lazy to give needed information to those he asks for help.

Bob

 

He's probably past the deadline to do the homework.

 

He is not only too lazy to do his own homework, he is too lazy to give needed information to those he asks for help.

Bob

Maybe he finished it on his own and he doesn't need your help. It's a giant leap to accuse him of being lazy. Maybe you could stop declaring new members as lazy or other negative things (see other posts on other threads) because OPs don't respond to your demands for clarifications on your timescale.

 

Maybe he finished it on his own

it is quite common that if you run to a dead end with your problem solving and decide to ask for assistance - your mind still latches through all available options AND . . . as you attempt to form a question the general public could decode - you will notice something from that very phrasing of your request that gives you a new lead . . . etc. . . .

 

it is quite common that if you run to a dead end with your problem solving and decide to ask for assistance - your mind still latches through all available options AND . . . as you attempt to form a question the general public could decode - you will notice something from that very phrasing of your request that gives you a new lead . . . etc. . . .

Yes, that, and he may have posted it on other websites related to electronics with more (or faster) viewers/helpers than ACC offered.

 

He's probably past the deadline to do the homework.

Maybe it is time we needed a new forum category/section, "Post Your Homework Here, We Do It For You" (ha ha)
That's probably what happens on other sites anyway

 

"Post Your Homework Here, We Do It For You"

Yes - but then it becomes our primary activity - besides - it will be highly questionable , that such would help anyone who are (in academic sense) dead anyway

 

hi Guys,
Remember the TS's Topic.
Mod

 

hi Guys,
Remember the TS's Topic.
Mod

Hi there Eric,

I think i misunderstood the original poster's question anyway. I thought he was asking about the general analysis based on current but then i see this:
" yes I have to derive output current equation "
That's a little different i think. That question is usually referring to the actual output current based on some op amp model that includes the output resistance or impedance.

I have a feeling it doesnt matter anymore though as the original poster seems to have left and if we wants a good answer he's going to have to clear up this question so we know exactly what kind of analysis he wants to do. There are just too many ways to do this and i dont think we should post all the methods (ha ha)

BTW i was just kidding about the "We do all your homework" section (har har) i just couldnt resist joking about that a little.

Take care for now,
Al