I am having problems with part b of the question i have working on. For part a) I have managed to find that the circuit is a Buck Converter (Step down converter) and that duty cycle is controlled by a OP AMP in comparator mode which creates a error voltage and is fed into the oscillator. ( I have included more information about the two states of the circuit, when the transistor is on, and when the transistor is off, included the free wheel diode etc, and the indoctors magnetic field collapsing).

For Part b), i am getting stuck, i take it you have to start at the voltage divider and try and work out R2. I have started this with the equation

\( V_{REF} = (\frac{R2}{R1 + R2} ) * V_{cc} \)

which re-arranges to
\( R2 = (\frac{V_{REF}}{V_{cc}} - 1) * V_{cc} \)

With Vcc being the voltage supply to the OP AMP which isn't supplied.

I have read that the value of R2 can also be given by the

\( R2 = \frac{V_{fb}}{I_{r1/2}} \)

With V_fb being the voltage to the non inverting input of the OP AMP, but also the current is not supplied for the equation. The current being the current going into R1 at the top of the voltage divider.

I am a little bit stuck, if anyone can point me in the right direction. Hopefully it is something simple i am missing! Or if i haven't explained myself very well!

Thanks for your help

 

I fear there is some information missing. Does it give the value of Vout anywhere?

 

Unless I'm missing something, that appears to be either a bad question or a trick question.
There does not seem to be enough info to determine the answer to b).
Without knowing the answer to a least one other variable (Vout), the answer can be any value for R2.
In other words, any arbitrary value for R2 can be solved for a Vin that satisfies there being a 30% duty-cycle with Vref=1.25V.
Edit: Albert beat me to it.

 

Hi crutschow and AlbertHall,

I thought the same thing, and i can't find anything else which helps in this kind of problem. Thats all the info i have got unfortunately.

Thanks for your help

 

Hi crutschow and AlbertHall,

I thought the same thing, and i can't find anything else which helps in this kind of problem. Thats all the info i have got unfortunately.

Thanks for your help

Hi Barry you are missing the E24 Series table upload a screenshot of that.

 

Hi Barry you are missing the E24 Series table upload a screenshot of that.

That doesn't solve the problem of insufficient information in the question to generate a unique answer.

 

Hello,

I get these two, this one:
R2=50000/(4*Vout-5)
and this one:
R2=250000/(6*Vin-25)

One is in terms of Vout and one in terms of Vin, but because we know neither Vin or Vout we cant solve it for a single number, just a function. That means we cant look in any table of preferred values and pick a single one. We can generate another function that does this for us automatically, but that is most likely not what the question is asking for. It is more likely that something is missing from the problem specification, namely the output voltage. If we knew that we could solve both questions. Since we dont know that, we can only write functions like those above.
There are many cases where the problems require solutions in the form of one or more functions, but this doesnt look like that.

 

The missing value is........ Vout=7.5V

 

The missing value is........ Vout=7.5V

Oh good, you've had your crystal ball repaired.

 

Is Barrys formula correct? What would the value of Vcc be?

 

Is Barrys formula correct? What would the value of Vcc be?

1. The first one is OK.
2. In that first equation Vcc is Vout.

But you still can't get R2, Vout, or Vin.

 

Should it not be Vout=vref*(R1+R2/R2)

Vout=1.25(10+2/2) = 7.5 meaning R2=2?

 

Should it not be Vout=vref*(R1+R2/R2)

Vout=1.25(10+2/2) = 7.5 meaning R2=2?

You can't just put in a value for R2 and then claim to have calculated it.
Vout=1.25((10+R2)/R2)=??

 

You can't just put in a value for R2 and then claim to have calculated it.
Vout=1.25((10+R2)/R2)=??

7.5V is the true value that was missing off the question no guess work or trial and error involved. Using the formula and through substitution it gives 7.5V the correct Vout value so R2 must be 2.

 

You went from:

Vout=vref*(R1+R2/R2)

To:

Vout=1.25(10+2/2)

In your second equation you have substituted the value of R2 with the number '2'. You are imposing the condition that R2 is equal to 2, so it is no surprise that that is the value that pops out of the formula.

 

You went from:


To:


In your second equation you have substituted the value of R2 with the number '2'. You are imposing the condition that R2 is equal to 2, so it is no surprise that that is the value that pops out of the formula.

Im just working backwards using an equation I found to determine Vout. So I now know Vout=7.5V as this was missing off the question (mistake of the lecturers). How else could you determine R2 now that Vout is known?

 

Your first equation:
Vout=vref*(R1+R2/R2) OK, except there should be brackets around the 'R1+R2' bit

Your second equation:
Vout=1.25(10+2/2) Here you have put in the value for R1 as 10, OK
But you have also put in a value of 2 for R2, hence it is no surprise that vaue pops out for R2.
What would happen if you put in 3 instead of 2?

 

Your first equation:
Vout=vref*(R1+R2/R2) OK, except there should be brackets around the 'R1+R2' bit

Your second equation:
Vout=1.25(10+2/2) Here you have put in the value for R1 as 10, OK
But you have also put in a value of 2 for R2, hence it is no surprise that vaue pops out for R2.
What would happen if you put in 3 instead of 2?

Then I would not get the correct 7.5 value for Vout

 

Then I would not get the correct 7.5 value for Vout

And you know 7.5V is correct because?

 

And you know 7.5V is correct because?

The teachers left the value out of the question by accident. They just realised their mistake.