BJT Common Collector Amplifier

Thread Starter

The_Cook

Joined May 29, 2014
48
Hi guys I need some help with starting this problem. For question (a) don't I need to draw the mid-band small signal amplifier equivalent circuit given below to calculate the base current, emitter current and rPI?

upload_2014-11-17_21-0-8.png
upload_2014-11-17_21-0-23.png
 

Jony130

Joined Feb 17, 2009
5,487
Your small-signal model is wrong. In CC amplifier Vo is across emitter, and emitter is not connected to GND the collector is .
 

Thread Starter

The_Cook

Joined May 29, 2014
48
Ok I was just basing it off of what was given with the question. So I'm guessing that's wrong?

Secondly for the first question how do I calculate the IB and IE and rPi?
 

Jony130

Joined Feb 17, 2009
5,487
Simply use this small-signal equivalent circuit

3.PNG
And draw the current

As for the part A, simply use circuit theory (KVL, KCL etc) and solve for Ib, Ie
 

dalam

Joined Aug 9, 2014
58
I have solved this taking some approximations.
I calculated Ib using KVL in the base emitter loop. I found it to be 18.87 micro amps.
Then to find Ic I used Ic=ßIb. It turns out to be 1.887 mili amps.
And Ie = (ß+1)Ib=1.9mili amps.
To find Rpi =ß/gm(trans conductance)= ß/(Ic/Vt)=1.377Kohms.
But my Ic does not matches with the one given in the question. Will you please tell me what am I missing here?
 

Jony130

Joined Feb 17, 2009
5,487
You have not missed anything, Ie is 1.9mA. But is doesn't matter, for small-signal analysis we assume Ic =2mA.
And re = 26mV/2mA = 13 ohm so Rpi = 101 * 13 = 1.313k ohm. As you can see not much different from yours Rpi.
 
Top