Hi. I an confused on how the biased clipper works. I understand the ideal diode acts as a short when forward bias and acts as an open when reversed bias. In the attached image, in figure A, I understand that that the input voltage has to be at least equal to Vb to conduct the ideal diode as shown. But when the diode is reversed in figure B, Im confused on how it produced that clipping at and below positive 4 volts. How can I simplify my analysis? Thanks.