# Basic distribution problem for a ripple voltage

#### KevinEamon

Joined Apr 9, 2017
284
Hi guys
I'm trying to get started with some studying here. Trying to reactivate the mathematical functionality of my brain, which is not going well.
I put pen to paper and realised Omg my maths has died.
.
Therefore this is going to seem really stupid but I have this equation I'm reading

Vr = Vp [1-(1-td/Rc) = Vp td / Rc

Now I'm sure that all looks perfectly legitimate to you and I'm sure it is.
But I like to know how it works out that way... so I can learn/understand it.

So to break it down: -

Vp [1-(1-td/Rc)]
Distribute the minus

Vp [1(-1+td/rc)]

Distribute the 1 is just

Vp (-1+td/rc)

and the Vp

-Vp + Vp td / rc

Right?

#### crutschow

Joined Mar 14, 2008
29,479
Are you sure there's not an e (natural exponential) in that equation?

#### KevinEamon

Joined Apr 9, 2017
284

That actually does work out when I put numbers into it.... hmm

Opps never mind silly me... ahhh sigh....

Last edited by a moderator:

#### MrAl

Joined Jun 17, 2014
8,864
You dont lose a term just because you simplify that minus sign.