Hey everyone.
So I'm absolutely stuck. I've found what I need, but it's $450 and about $430 over my budget.
What I need: A regulator to drop either 5v or 12v down to 2.9v, still allowing at least 120w and 40a.
What it's powering: An 8 GPU video card with 2 ground, a 3.3v and 2.9v terminals. (It has a power supply board with a plug in and is bolted to the card [bolts transfer the power] but I can easily connect the wires to the card's terminals). The GPUs take the 2.9v, but it's confusing. The board says 2.7v on the terminal, the power board says 2.9v and the real PSU says 2.9v. So apparently... it's 2.9v >_>. Here's the best info on it I can provide:
http://www.thedodgegarage.com/3dfx/q3d_aalchemy.htm
My plan: I figured I'd get 2 of these fairly cheap computer PSUs and run them in parallel. If I use the 12v->2.9v method, then I have 2 rails to deal with per PSU. However, the '2 rails' are most likely (due to the cheapness of the PSU) just a split of one main rail and either current regulated or not. And I'd need to know which all 12v lines I solder together, as well as the grounds, would I use the -12v line? If I do the 5v->2.9v method, then there is no dual rails, but the max current put out is about 16a less. Same Q on grounds, -5v this time?
Skills: Cars and computer hardware. I know very very little about the stuff I'm dealing with, which I feel falls into Electrical Engineer and Computer Science. The 2 friend's I've consulted really weren't much help lol One is a Comp Sci grad, the other has worked in a PCB facility and knows a bit about this stuff, but again neither has sadly helped much. I know quite a bit about computers, how they work, building systems and overclocking. I'm Mr Fix-It to many people when a computer problem crops up, but this stuff stumps me.
I've looked into resistors, capacitors, diodes, bench top power supplies (expensive), already made regulators (pricey or not putting out the needed voltage) and pots. The other chap who's in my same predicament has been using a pot and gets the card to boot, output video and be read by drivers, but when he goes to test 3D the card locks up. My Comp Sci friend explained that when a pot has current draw the voltage drops and that's probably the problem.
I read a bunch of the pages in "Volume III - Semiconductors » DIODES AND RECTIFIERS »" and the Diode's part helped me understand thing quite a lot. That part where my friend's hadn't helped me much comes into play there. The one mentioned that the voltage that the Zeners are showing for specs equate to the drop they provide, where as I've now learned it's what they actually output. That was what I assumed when I first look at the specs :| So instead of needing a 9.1v diode to drop the 12v down to 2.9v, I need just a 2.9v diode. Problem there is they are all rated at 20-140mA, and assuming I understand things correctly, if I ran them in parallel I'd need between 450-1800. Again assuming I understand things correctly, with their power dissipation (what is lost during conversion?) I'd only have about 80w left over to power the card, assuming I use the 500mW.
And if you're interested, here's what I've found that doesn't meet my specs, and is far too expensive.
These ones are damn close to what I need, and are only $8. I suppose I could boost the voltage from 2.5, if that's possible. (Isolated DC/DC Converters)
http://www.cherokeepwr.com/product/dcdc.aspx
Then there's this, which is exactly, 100%, what I need. Could even do with 2 less chips and have a total current rating of 80A instead of the 4 chip 160A. At first I WAS looking at the chip and when I searched for it to buy, was $18 and got happy thinking it was the whole card. Then I realized my error and was sad again
http://www.irf.com/technical-info/refdesigns/irdcip2003a-c.pdf
So I come, begging, pleading, for a solution!!
Thank you,
-Clint
So I'm absolutely stuck. I've found what I need, but it's $450 and about $430 over my budget.
What I need: A regulator to drop either 5v or 12v down to 2.9v, still allowing at least 120w and 40a.
What it's powering: An 8 GPU video card with 2 ground, a 3.3v and 2.9v terminals. (It has a power supply board with a plug in and is bolted to the card [bolts transfer the power] but I can easily connect the wires to the card's terminals). The GPUs take the 2.9v, but it's confusing. The board says 2.7v on the terminal, the power board says 2.9v and the real PSU says 2.9v. So apparently... it's 2.9v >_>. Here's the best info on it I can provide:
http://www.thedodgegarage.com/3dfx/q3d_aalchemy.htm
My plan: I figured I'd get 2 of these fairly cheap computer PSUs and run them in parallel. If I use the 12v->2.9v method, then I have 2 rails to deal with per PSU. However, the '2 rails' are most likely (due to the cheapness of the PSU) just a split of one main rail and either current regulated or not. And I'd need to know which all 12v lines I solder together, as well as the grounds, would I use the -12v line? If I do the 5v->2.9v method, then there is no dual rails, but the max current put out is about 16a less. Same Q on grounds, -5v this time?
Skills: Cars and computer hardware. I know very very little about the stuff I'm dealing with, which I feel falls into Electrical Engineer and Computer Science. The 2 friend's I've consulted really weren't much help lol One is a Comp Sci grad, the other has worked in a PCB facility and knows a bit about this stuff, but again neither has sadly helped much. I know quite a bit about computers, how they work, building systems and overclocking. I'm Mr Fix-It to many people when a computer problem crops up, but this stuff stumps me.
I've looked into resistors, capacitors, diodes, bench top power supplies (expensive), already made regulators (pricey or not putting out the needed voltage) and pots. The other chap who's in my same predicament has been using a pot and gets the card to boot, output video and be read by drivers, but when he goes to test 3D the card locks up. My Comp Sci friend explained that when a pot has current draw the voltage drops and that's probably the problem.
I read a bunch of the pages in "Volume III - Semiconductors » DIODES AND RECTIFIERS »" and the Diode's part helped me understand thing quite a lot. That part where my friend's hadn't helped me much comes into play there. The one mentioned that the voltage that the Zeners are showing for specs equate to the drop they provide, where as I've now learned it's what they actually output. That was what I assumed when I first look at the specs :| So instead of needing a 9.1v diode to drop the 12v down to 2.9v, I need just a 2.9v diode. Problem there is they are all rated at 20-140mA, and assuming I understand things correctly, if I ran them in parallel I'd need between 450-1800. Again assuming I understand things correctly, with their power dissipation (what is lost during conversion?) I'd only have about 80w left over to power the card, assuming I use the 500mW.
And if you're interested, here's what I've found that doesn't meet my specs, and is far too expensive.
These ones are damn close to what I need, and are only $8. I suppose I could boost the voltage from 2.5, if that's possible. (Isolated DC/DC Converters)
http://www.cherokeepwr.com/product/dcdc.aspx
Then there's this, which is exactly, 100%, what I need. Could even do with 2 less chips and have a total current rating of 80A instead of the 4 chip 160A. At first I WAS looking at the chip and when I searched for it to buy, was $18 and got happy thinking it was the whole card. Then I realized my error and was sad again
http://www.irf.com/technical-info/refdesigns/irdcip2003a-c.pdf
So I come, begging, pleading, for a solution!!
Thank you,
-Clint