Hi,
In the figure below, AB=BC=CD. If the area of triangle CDE is 42, what is the area of triangle ADG.
See the attached figure in the next post. I cant upload it here.
I think we can start from area of triangle which is given by:
Area of triangle CDE = ½ * CE * DE
Or 42 = ½ * CE * DE
I can do some work to transform CE into AD or in my opinion AD = 3 * CE. But the question does not provide any relation between DE & DG. This is what I want to know.
Somebody please guide me how to solve it.
Zulfi.
In the figure below, AB=BC=CD. If the area of triangle CDE is 42, what is the area of triangle ADG.
See the attached figure in the next post. I cant upload it here.
I think we can start from area of triangle which is given by:
Area of triangle CDE = ½ * CE * DE
Or 42 = ½ * CE * DE
I can do some work to transform CE into AD or in my opinion AD = 3 * CE. But the question does not provide any relation between DE & DG. This is what I want to know.
Somebody please guide me how to solve it.
Zulfi.