area of periodic signal

\(
X_{avg} \; = \; \int_{-\infty}^{+\infty} x(t) dt
\)

average of periodic signal

\(
X_{avg} \; = (1/T)\; \int_{-\infty}^{+\infty} x(t) dt
\)

am i right?

 

Are you looking for total area or net area?

If your integration limits are from -∞ to +∞, what is your period T.

Why are you using the same parameter, Xavg, for both. This implies that they are equal.

 

sorry i dont aware of coding that much its just copy of your last post to me on even and odd title question

Are you looking for total area or net area?

net area is something integrated over some period and total area is area over full interval

example y=x limt -2 to 2
area under 0 to 2 give net area(excluding negative axis curve) and are under -2 to 2 give total area isnt it?

If your integration limits are from -∞ to +∞, what is your period T.

Then sure my limit is infinity

Why are you using the same parameter, Xavg, for both. This implies that they are equal.

\(
X_{area} \; = \; \int_{-\infty}^{+\infty} x(t) dt
\)



\(
X_{avg} \; = (1/T)\; \int_{-\infty}^{+\infty} x(t) dt
\)