The 7406 and 7407 chips are inverting and noninverting (respectively) buffers (6 of them) with open collector outputs. The open collector output allows you to apply higher voltage to the output side. You still need to power the chip with the lower voltage (5 VDC), but you have more freedom on the output.Is there a IC chip that the Vdd can be attached to 13v, that can receives a 5v to 0v digital signal and send the same digital signal out as 13V to 0v?
I have 6 digital inputs that need to be converted to 13v digital.
The 7407 and 7406 don't have this type of push-pull complementary output stage. It is a single NPN open collector output.Thank You. Can you elaborate how it takes a Vcc of 5v and amplify it to 13v at the outputs?
Here's what I want to do but use an IC instead of 12 separate transistors:
View attachment 40063
I thought the minimum gate source was 10V, can I us these to put 5v to the gate and 13v to the source?Hello,
Would it not be better to use a logic gate mosfet like the IRL540?
I have attached both datasheets for comparison.
Bertus
I would use the 7406 or 7407 chips as steveb suggested. They are cheap, will do what you want, and requires only one chip (and six resistors) to convert your six signals.
You use a pull up resistor on the output pin. Just tie that resistor to 13 VDC. The datasheet shows how to calculate the resistor value.I'm having trouble understanding... with a 5v input what determines the 13v output? can you sketch a quick schematic so I can understand?
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