Hi
Can someone tell me what i have done wrong in the following question:

View attachment tut6_qns.doc

Equation 1

Vo=10V

Equation 2

Z = j4*j6/4j+j6 = -24/j10

Vo= (-j2.4)/(j4+6-j2.4) * 12 = -j48/(j1.6+6) = 11.95+j7.4689

Equation 3

2H -> j4
1/12F -> j6

Z = (6*j6)/(6+j6) = -6j+6

Vo = (j6)/(j4+6)*4 = (j24)/(4j+6) * (j4-6)/(j4-6) = (-96-144j)/(-16-36)
= 1.816-j2.769


P.S

 

The capacitive impedance in the case of equation 2 is -j4Ω not +j4Ω.

So the parallel branch impedance is -j4*j6/(j6-j4)=-j12Ω

Remember Zcap=1/(j*ω*C)=-j/(ω*C)

 

for equation 2 i get

12j/(12j+6) * 12 = 1.60.8j
in phasor = 1.788/26.6 degrees