The the capacitor is characterized in two-electrode system by CV, and both the two electrodes are supposed to be exactly the same.
Then the capacitance can be calculated from:
C=A/Ev
E is the potential window in CV, that the gap between the two potential limits
and v is the scanning rate
Since A can be obtained from the integral of cyclic voltammograms..I don't it's integrated from the positive sweep (or negative sweep) cyclic voltammograms..or both the positive and negative ones..
thx..
Then the capacitance can be calculated from:
C=A/Ev
E is the potential window in CV, that the gap between the two potential limits
and v is the scanning rate
Since A can be obtained from the integral of cyclic voltammograms..I don't it's integrated from the positive sweep (or negative sweep) cyclic voltammograms..or both the positive and negative ones..
thx..