Evening, A newbie to the world of electronics and I am shamelessly on the scrounge for some urgent assistance,
To cut a long story short I have a home build kitcar going for its IVA test in a week and I have discovered a flaw in braking system circuit. I am sure the fix is an easy one but with the test looming I am pushed for time. To cut to the chase the circuit it is as follows;
A brake reservoir with a float has two wires. One to the vehicle ground, the other to a dash unit. With the float up, or reservoir full, there is no continuity between the wires(tested with the continuity tester on my multi meter). With the float down, or reservoir empty, there is continuity. This in theory then grounds the connection at the dash unit, completing the circuit and illuminating a dash warning light.
My problem is this this, its not opearting like I expected it to, ie the switch in the reservoir does not appear to be simple on off switch, When the circuit is energised as described with the 12v from the car electrical system the dash warning LED remain illuminated at all times, regardless of where the float is, unless I physically remove the earth wire. I think the reason for this is because the switch is actually a variable resistor and not a switch, with the float up the resistance measures .505 K ohm. With the float down ( reservoir empty) the resistance drops to 0. The system draws 3.5ma when the LED is illuminated. So basically what i am looking for help with is a circuit that provides the ground connection, the continuity when he resistance is zero (the float is down) but when the resistance remains greater than that, ie at .5 kohm (the reservoir full) the connection with ground remains broken and the warning lamp off. Can anybody help me with this
In programing terms I would be needing Float resistance = X
if X > 0 ohm then Ground to dash is Off
Else
Ground to dash is on ( and connection to earth is made, lamp illuminates).
I hope this makes sense and thank you for taking the time to read this.
Kind regards
Hec
To cut a long story short I have a home build kitcar going for its IVA test in a week and I have discovered a flaw in braking system circuit. I am sure the fix is an easy one but with the test looming I am pushed for time. To cut to the chase the circuit it is as follows;
A brake reservoir with a float has two wires. One to the vehicle ground, the other to a dash unit. With the float up, or reservoir full, there is no continuity between the wires(tested with the continuity tester on my multi meter). With the float down, or reservoir empty, there is continuity. This in theory then grounds the connection at the dash unit, completing the circuit and illuminating a dash warning light.
My problem is this this, its not opearting like I expected it to, ie the switch in the reservoir does not appear to be simple on off switch, When the circuit is energised as described with the 12v from the car electrical system the dash warning LED remain illuminated at all times, regardless of where the float is, unless I physically remove the earth wire. I think the reason for this is because the switch is actually a variable resistor and not a switch, with the float up the resistance measures .505 K ohm. With the float down ( reservoir empty) the resistance drops to 0. The system draws 3.5ma when the LED is illuminated. So basically what i am looking for help with is a circuit that provides the ground connection, the continuity when he resistance is zero (the float is down) but when the resistance remains greater than that, ie at .5 kohm (the reservoir full) the connection with ground remains broken and the warning lamp off. Can anybody help me with this
In programing terms I would be needing Float resistance = X
if X > 0 ohm then Ground to dash is Off
Else
Ground to dash is on ( and connection to earth is made, lamp illuminates).
I hope this makes sense and thank you for taking the time to read this.
Kind regards
Hec