Hey I read this solution for calulating the mulitplcation of (09)H & (04)H in Assembly Language Programming for 8085.
I am not sure how the RAL works in this case, Help me out please.

MVI A, 09
RAL
RAL
RST 1

 

Shifting a binary number 1 bit to the left is the same as multiplying it by 2.
Try it for yourself with a pencil and paper on a couple of simple binary numbers!

 

Hello,

The RAL command is one of the undocumented commands.
Here is an explanation:

RAL (Rotate left through carry)  
(An+1) <-- (An); (CY) <-- (A7); (A0) <-- (CY) 

00010111 

Flags: CY 

This comes from this page:
http://www.geocities.com/bschhabra/instruction.html

Greetings,
Bertus

 

hey thanks friends, I think my problem is solved