Here's the thing about an emitter follower - the emitter voltage will rise with load current, and so Vbe will fall to the point where the transistor has almost shut off. You will not have the full voltage across the base resistor. With a capacitive load, the transistor will shut off completely and the base resistor ends up with 0 volts across it. You might even delete it from the circuit. In the simulation in post #16, with a 250ohm base resistor, the gate is charged and NPN transistor is turned off by 0.2us. The discharge is essentially 0 ohms through the 2N2369, and takes only 0.1us. Your 1K base resistor might stretch these out to 0.5 - 0.8us in both directions.IF I reduce it to 100Ω then that'd be 120 mA and the 555 is rated for 200 mA if I read the data sheet right.
What is meant by Probe @ "Negative" and "Collector"? Aren't these the same node? It's labeled "Out" in the schematic in post #16. Please clarify.Since scope probe is at negative, the IGBT is almost always on, pulling the voltage across the bulb to ground. That's why it looks like it's nearly full off. It's nearly fully grounded.
It sounds like it's working pretty well. That ringing is crazy though. It hits -12V! I wonder where the inductance is coming from?The lamp can be lit to near full brightness or dimmed to the point where it extinguishes. When a small computer fan is placed as a load the fan goes from near full to near stopped.
It takes time for voltage to rise and drop- nothing is instant.Looking at the data sheets for the 2N3904 and 3906 transistors.
What does "Delay" "Rise" "Storage" and "Fall" times mean? Aside from the obvious - they have to do with timing. Most curious about "Storage". (see below for my issue)
_3904 ________________ 3906_
-35 nS ---- Delay --- 35 nS
-35 nS ---- Rise ---- 35 nS
200 nS -- Storage - 225 nS
-50 nS ---- Fall ----- 75 nS
This circuit (in part) (below) is operating at 12 volts. R2 is a square wave input (high / low). The 3906 is getting warm. After a minute of operation I'm measuring a case temperature of 99˚F. This is concerning! The red line is 12 VDC (no resistance) and the black line out of the bottom of the 3906 goes direct to ground. This should only be charging and discharging an IGBT Gate.
The IGBT gate capacitance is:
Cies --- Input Capacitance --------------- 5770 -- pF VGE = 0V /// VCC = 30V
Coes -- Output Capacitance ------------- 400 --- pF
Cres -- Reverse Transfer Capacitance ---- 100 --- pF
View attachment 197363Cut and pasted from a larger diagram. Available if necessary - but many have already seen it.
Cies --- Input Capacitance ------------ 5770 pF VGE = 0V /// VCC = 30V
Coes -- Output Capacitance ---------- 400 pF
Cres -- Reverse Transfer Capacitance - 100 pF
Tried it. Don't know why it wouldn't work.Any reason why you are not driving the gate directly from the '555?
Bob
This is the scope after putting a 102 cap (1000 pF) across power and ground as close as possible to the chip.I don't see any decoupling capacitors.
Yes. But set to 1X.(you are using a 10:1 probe?)
Why?Yes. But set to 1X.