djsfantasi
- Joined Apr 11, 2010
- 9,163
That’s a good observation!
However, for the second digit of the seconds and minutes, when do you need a reset?
However, for the second digit of the seconds and minutes, when do you need a reset?
Umm for the tens? Or the units?That’s a good observation!
However, for the second digit of the seconds and minutes, when do you need a reset?
Is the second digit of minutes (or seconds), the tens or units?Umm for the tens? Or the units?
If for the units, the moment they reach 9 they need to send a signal to the tens, and if for the tens, they need to send a signal the moment they reach 5. Which is another problem... maybe with AND gate for each of them individually?
From left to right which we read the clock... means the units. The AND gate is not required there, we can connect Qd to A clock of 7492 and send the signal through there. And use the AND gate for the tens numbers. Please correct me if i'm making mistakeIs the second digit of minutes (or seconds), the tens or units?
And consider whether or not an AND gate is required.
But look at how the schematic you found has the 10's second counter wired. They have the clock from the 1's second counter going to the A clock and it should be going to the B clock. They have the B clock coming from QA and that implements divide by 12 functionality.for the tens we're using 7492 because it has a 12 mod and a 6 mod
Ok now wit this table i'm getting a bit confused... can you open it a little bit more?Also look at the count sequence for the divide by 6:
View attachment 256209
It's 0, 1, 2, 4, 5, 6. That's okay for a divide by 6, but not for the 10's second counter. It needs to count in the normal order.
When you use 7492 as a divide by 6, you only use the B, C, and D flip flops and feed the clock to the CLKB input. If you look at the table, and ignore the A output, you can see the count sequence isn't what you need.Ok now wit this table i'm getting a bit confused... can you open it a little bit more?
That makes sense... now i think i'm understandingWhen you use 7492 as a divide by 6, you only use the B, C, and D flip flops and feed the clock to the CLKB input. If you look at the table, and ignore the A output, you can see the count sequence isn't what you need.
What is the name of this class, school, and teacher?That makes sense... now i think i'm understanding
Unfortunately yes, college level, they didn't give us any kind of instructions, and i'm living in middle east unfortunately... so... there's nothing i can do with their names i guess.What is the name of this class, school, and teacher?
I find it unusual that a teacher wouldn't give better instructions, but not so unusual for a student to miss some important information because they didn't realize it was important or weren't paying attention. Is this college level?
Still, it's unusual for a student to be given an assignment where they don't even know where to start.college level
I really appreciate any help i can get, it's a group project, and most of my classmates are not even fluent in english like me to ask question around.Still, it's unusual for a student to be given an assignment where they don't even know where to start.
We can give guidance, but it's helpful for us to know what the constraints are so we don't head you down the wrong path. I don't remember learning to use commercial counters in college, but it was a long time ago.
You can use all 7490, all 7492, or a combination. There's an advantage for using 7490 for the second and minute counters (do you know why), but all of the other counters will require logic to reset them at appropriate counts.I am allowed to use 7492, 7490
Unfortunately I must do a combination. What's the advantage of using 7490 for minute and second counter?You can use all 7490, all 7492, or a combination. There's an advantage for using 7490 for the second and minute counters (do you know why), but all of the other counters will require logic to reset them at appropriate counts.
Is there a reason why you're being told to use standard TTL? CMOS is less expensive these days and uses less power.
The minutes and seconds each require a modulo 6 and a modulo 10 counter. What types of counters are 7490 and 7492?What's the advantage of using 7490 for minute and second counter?
Since CD4033 have outputs for seven segment displays, decoding a specific count can be more involved than decoding from binary outputs.i originally had plan to do it with 4033
Because it doesn't have a mod 10 counter? And if it doesn't have, which counter does have?@arian78
Actually you can't use all 7492. Can you explain why?
Hi arian,While 7490 has only a mod 6 counter which makes it perfect for tens of minutes and seconds, but we can't use it for hours units at all?
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