UNDERSTANDING.....!!!! WHY WE SHOULD CONNECT A RESISTOR IN SERIES WITH LED
Friends we know that resistor is a current limiting component and it is also a voltage divider..
volt
I will show you how voltage will be divided by considering a simple led circuit ..
Friends I have one RED LED whose Power Rating as below
Standard Red LED
Max.Voltage 1.7V
Max.Current 10mA
Now if I want to glow My LED in sufficient Manner Means I want to use 1.7 Volts DC power supply but we cant get 1.7 Volts DC voltage Source (cell or battery )in market. Instead of that I have a DC voltage Source(Cell or Battery) of 9 Volts. then what should I do now...? Because if I connect a 9 Volt Dc source to that LED means Definitely My LED will Burn out...
so without burning LED and using 9 Volt Battery I want Glow LED in a sufficient Manner....
Then How It is possible..........?
yes, it it is possible to glow a 1.7 Volt LED with 9 Volt DC source ,by connecting a Resistor in series with LED
Working Of Resistor:
Friends all are Tells only that, Resistor is Electronic Component which limits the flow of current. But also Helps to divide the Voltage
I give you Simple formula that
Finding Resistor Value to Divide or provide an output of 1.7 Volts from 9 Volt Battery
i.e,
Resistance= Input Voltage - Output Voltage
Required current
R= 9 Volt -1.7 Volt
10mA
R= 730 Ohm
It Means that if I give 9 Volts as a input to 730 Ohm Resistor means My output will be 1.7 Volts with 10 mA Current.
1.73 Volts Is given to led and remaining 7.3 voltage is dropped across resistor ..
Friends we know that resistor is a current limiting component and it is also a voltage divider..
volt
I will show you how voltage will be divided by considering a simple led circuit ..
Friends I have one RED LED whose Power Rating as below
Standard Red LED
Max.Voltage 1.7V
Max.Current 10mA
Now if I want to glow My LED in sufficient Manner Means I want to use 1.7 Volts DC power supply but we cant get 1.7 Volts DC voltage Source (cell or battery )in market. Instead of that I have a DC voltage Source(Cell or Battery) of 9 Volts. then what should I do now...? Because if I connect a 9 Volt Dc source to that LED means Definitely My LED will Burn out...
so without burning LED and using 9 Volt Battery I want Glow LED in a sufficient Manner....
Then How It is possible..........?
yes, it it is possible to glow a 1.7 Volt LED with 9 Volt DC source ,by connecting a Resistor in series with LED
Working Of Resistor:
Friends all are Tells only that, Resistor is Electronic Component which limits the flow of current. But also Helps to divide the Voltage
I give you Simple formula that
Finding Resistor Value to Divide or provide an output of 1.7 Volts from 9 Volt Battery
i.e,
Resistance= Input Voltage - Output Voltage
Required current
R= 9 Volt -1.7 Volt
10mA
R= 730 Ohm
It Means that if I give 9 Volts as a input to 730 Ohm Resistor means My output will be 1.7 Volts with 10 mA Current.
1.73 Volts Is given to led and remaining 7.3 voltage is dropped across resistor ..