Sorry for the naive question, but I'm just wondering why can't we kill all the ripples by using a capacitor with a large capacitance instead of other more sophisticated methods ?
Not only on power-up but all the time.3) Large farad capacitors act more like a short circuit on power-up
Those sophisticated methods do more than just "kill all the ripples", such as regulating the voltage, limiting the current, and providing short-circuit protection.why can't we kill all the ripples by using a capacitor with a large capacitance instead of other more sophisticated methods ?
Because, all other factors aside, it would require an infinite capacitance to kill all the ripple. As soon as the capacitor supplies a single electron of charge to the current, the voltage across it changes and, hence, you have ripple. The more current the load needs, the more ripple you have for the same capacitor.Sorry for the naive question, but I'm just wondering why can't we kill all the ripples by using a capacitor with a large capacitance instead of other more sophisticated methods ?
It's not a HW, that would be awful xD. I am working on building my own power supply for testing breadboard circuits in general.On further consideration, this sounds an awful lot like a homework question. Is it?
The old standby, the LM317 adjustable regulator is often used for that purpose.I am working on building my own power supply for testing breadboard circuits in general.
That is a super doc, I had and lost and now have. Thanks very much. Just good reading.Hello,
Have a look at the pages 34 and 35 of the attached PDF fro the effect of the capacitor value and the load resistance.
Bertus
also a large capacitor takes too long to charge and discharge, a small value cap smoothes out the leftover rippleBesides, just using a huge capacitor does eluminate all if the ripple, and it does very little if anything for regulation, which is sometimes
Important.
by Jake Hertz
by Jake Hertz
by Jeff Child