Let's forget about that 1Ω resistor and suppose that we have a circuit that is the same as in the picture up to the 4Ω resistor. If I try to
solve that circuit I have two unknown node voltages and only one equation! Why I can't find a second equation? But if I include that 1Ω
resistor, KCL will give me one more equation that includes \( V_{A} \) and \( V_{B} \) and I will be able to solve for \( V_{B} \) .
I know that I can find \( V_{th} \) by taking into consideration that 1Ω resistor, but the question is why I can't solve the circuit without that
1Ω resistor.
So assume that the 6 and 4Ω are in series and the 1Ω is disconnected from the circuit.
Thank you.
solve that circuit I have two unknown node voltages and only one equation! Why I can't find a second equation? But if I include that 1Ω
resistor, KCL will give me one more equation that includes \( V_{A} \) and \( V_{B} \) and I will be able to solve for \( V_{B} \) .
I know that I can find \( V_{th} \) by taking into consideration that 1Ω resistor, but the question is why I can't solve the circuit without that
1Ω resistor.
So assume that the 6 and 4Ω are in series and the 1Ω is disconnected from the circuit.
Thank you.