Current Divider Problem, Can't Solve

Discussion in 'Homework Help' started by yan500, Oct 6, 2011.

  1. yan500

    Thread Starter Member

    Jul 12, 2011
    Hey all, I'm stuck on this current divider problem. It's just killing me, I've been trying to solve it for an hour and a half now. I've combined and uncombined the circuits in about all the ways possible but I just can't get the right answer. Can someone help me out?
    Here's the problem setup:

    Is: 14.25 mA R1= 71k ohms R2= 21k ohms R3= 4k ohms R4 = 65k ohms R6= 31k ohms R7 = 34k ohms and R8 = 76k ohms

  2. t_n_k

    AAC Fanatic!

    Mar 6, 2009
    Start by lumping R3,R4,R6,R7 & R8 together as a single value.

    This value is 68.834k

    R1 & R5 play no part in the current distribution.

    So I2=14.25mA*68.834/(21+68.834)=10.919mA.

    Now find the current in R4 since you know I2.

    You then look at the current division of the current in R4 between the parallel combination R3||(R6,R7 & R8 combined) to deduce I3.

    And so on ....
  3. JoeJester

    AAC Fanatic!

    Apr 26, 2005
    Post your work ....