ElectricSpidey
- Joined Dec 2, 2017
- 2,786
The LED clamps the voltage at it's anode to something around 2 V. That means that when you press S1, the transistor acts like the collector is an emitter (with the collector open-circuited) which means that it basically acts like a diode. You are thus putting two 680 Ω resistors almost in parallel.The LED is connected directly to ground, it's connected to positive rail through the resistor at B28 (next to 2 orange jumpers)
Sorry another goof, I've reversed the LED in the schematic below
Thanks, the circuit does work as I said but could you explain how more current flowing through the LED when only S1 ( right button in breadboard shot) is being pressed?
Here's a simple example of a transistor NAND circuit driving an LED.Excellent point eetech, especially considering I'm trying to build up to making a basic computer :$
Thanks everyone for being so amazingly helpful, especially given how badly I explained myself.
I'm trying to build up my intuition and understanding by creating things myself, I think it's more productive than simply copying a schematic to a breadboardIf you want to make an old fashioned RTL logic gate then why not look at its datasheet and simply copy it?
Thanks I'll need to look up spice I think
I'm trying to build up my intuition and understanding by creating things myself, I think it's more productive than simply copying a schematic to a breadboard
R5 does prevent a supply short when both buttons are pressed, but a better way to look at it is that when both transistors are off, R5 provides the logic HIGH.Firstly my impression from looking at the schematic is that R5 is required to prevent a short when both PBA and PBB are pressed in the AND circuit and R7 prevents current flow to the base of Q3 when both are pressed because it's higher than R5.
Since the collector resistors affect how much current the gate can source, you want it appropriately small, but not so small that you waste power. When logic gates are designed, one of the things you have to define is fan out; how many other gate inputs you can drive without affecting the output logic level enough to affect circuit function.Is it just a rule of thumb that if you don't want current to "overflow" down another path you should double the resistance at that path? And if so why 2200 ohm specifically? Was it just the next resistor in the parts bucket or is it to err on the side of caution or is there a much more mathematical approach that brought you specifically to 2200?
Engineering is both an art and a science. The art is learning from your own mistakes and the science is learning from the mistakes of others.Thanks I'll need to look up spice I think
I'm trying to build up my intuition and understanding by creating things myself, I think it's more productive than simply copying a schematic to a breadboard