I have posted on these forums recently about wanting to build a 100W vacuum tube guitar amplifier. I was sufficiently cautioned to not even attempt anything like that before I have learned a lot more about electronics. So... I have moved on (down) to a guitar effects pedal. I bought the PCB online, and I ordered all the components from Digikey. I have a breadboard, and I am ready to breadboard this thing, see if it works, and then populate the PCB.
And I think I could do all that successfully. However, it doesn't really teach me all that much about how a distortion pedal works. Here is the schematic for the pedal I am building. I sat down this morning to look at it and try to explain (to myself) how the signal flows through the circuit. I could not even get past the "input". LOL!!!
If you look at the schematic, in the lower left-hand corner, you see the word "IN". It appears to me that there are two "INs" since I see two circles with a line. No idea what that's about. (?). But... That "IN" represents a standard mono 1/4" instrument-cable jack that is coming from the output jack of an electric guitar. So the tiny 0.13 mA, 1.2 mV (peak-to-peak) guitar signal enters the circuit... I don't exactly know what happens. It looks like the signal splits in half and goes in two directions, half through a 1 MOhm resistor (R1), and the other half through a a 33KOhm resistor (R2). Then the signal coming from R2 enters a capacitor, while the signal leaving R1... well... I really don't know what happens there, as it looks like it goes down a line splitting off several times to go through more resistors.
I know that I must be missing some fundamental principal here. For example, the input jack... it appears to have two circle/line icons. Is that because a standard mono instrument jack has a positive and a ground? One of those circles = ground? I have also heard it said that guitar jacks have a positive and a neutral. Is "neutral" and "ground" the same thing?
And I think I could do all that successfully. However, it doesn't really teach me all that much about how a distortion pedal works. Here is the schematic for the pedal I am building. I sat down this morning to look at it and try to explain (to myself) how the signal flows through the circuit. I could not even get past the "input". LOL!!!
If you look at the schematic, in the lower left-hand corner, you see the word "IN". It appears to me that there are two "INs" since I see two circles with a line. No idea what that's about. (?). But... That "IN" represents a standard mono 1/4" instrument-cable jack that is coming from the output jack of an electric guitar. So the tiny 0.13 mA, 1.2 mV (peak-to-peak) guitar signal enters the circuit... I don't exactly know what happens. It looks like the signal splits in half and goes in two directions, half through a 1 MOhm resistor (R1), and the other half through a a 33KOhm resistor (R2). Then the signal coming from R2 enters a capacitor, while the signal leaving R1... well... I really don't know what happens there, as it looks like it goes down a line splitting off several times to go through more resistors.
I know that I must be missing some fundamental principal here. For example, the input jack... it appears to have two circle/line icons. Is that because a standard mono instrument jack has a positive and a ground? One of those circles = ground? I have also heard it said that guitar jacks have a positive and a neutral. Is "neutral" and "ground" the same thing?