Wolframore
- Joined Jan 21, 2019
- 2,610
It's not condescending, it's just a fact our brains seem to operate differently and on different levels. It's possible to modify your electrical intuition even for low-frequency circuit design. I see circuit operation in terms of the classical EM field view (reactive and/or radiative as needed) because it simplifies understanding for me from the quantum view I need to think at when working with material science and solid state physics for semiconductor process troubleshooting. The fog description was a poor translation of that mental process. Maybe fruit salad would have been better.I never said I didn't understand, so please drop the condescending attitude.
I just don't think you need to look at current and voltage when doing a low-frequency circuit design from an EM field point of view.
It buys you nothing but a less clear (foggy) picture of the circuit operation.
Well that explains your view.I see circuit operation in terms of the classical EM field view (reactive and/or radiative as needed) because it simplifies understanding for me from the quantum view I need to think at when working with material science and solid state physics for semiconductor process troubleshooting.
+1Well that explains your view.
Most of us can work with circuits without have to use (or needing) a "quantum view" of their operation.
So all these posts were just to establish that?+1
That's exactly why understanding electrons is unnecessary to working with electronics at the circuit level.
No. https://forum.allaboutcircuits.com/...do-they-divide-or-choose.159367/#post-1387484So all these posts were just to establish that?
Could you say, @nsaspook , what is it?I moved on to something better.
Here is a book that explains most of it.Could you say, @nsaspook , what is it?
You always intrigue me, must admit.
https://onlinelibrary.wiley.com/doi/pdf/10.1002/0471433934.fmatterA practical new approach that brings together circuit theory and field theory for the practicing engineer
To put it frankly, the traditional education of most engineers and scientists leaves them often unprepared to handle many of the practical problems they encounter. The Fields of Electronics: Understanding Electronics Using Basic Physics offers a highly original correction to this state of affairs.
Most engineers learn circuit theory and field theory separately. Electromagnetic field theory is an important part of basic physics, but because it is a very mathematical subject, the connection to everyday problems is not emphasized. Circuit theory, on the other hand, is by its nature very practical. However, circuit theory cannot describe the nature of a facility, the interconnection of many pieces of hardware, or the power grid that interfaces each piece of hardware.
The Fields of Electronics offers a unique approach that brings the physics and the circuit theory together into a seamless whole for today's practicing engineers.
This book provides a new way to understand the subject of electronics. The central theme is that all electrical phenomena can be explained in terms of electric and magnetic fields. Beginning students place their faith in their early instruction. They assume that the way they have been educated is the best way. Any departure from this format just adds complications. This book is a departure—hopefully, one that helps.
Space is a inductor, a capacitor and a non-dissipative resistor. An example is the Z0 of a transmission line which is mostly resistive yet non-dissipative.See I’ve brought this up the the past... wires are inductors!!!!
The good Dr. is not discrediting simple applications of KVL, he's showing, like you did, that modified KVL (adding EMF sources) is really a Faraday law solution to a non-conservative field problem, not KVL as defined with conservative fields (a electrostatic field being conservative). A version of KVL that is completely consistent with Faraday's Law is Faraday's Law.I probably shouldn't be throwing myself into this, but I found the KVL test / mismatched voltage measurement question fascinating. Having said that, I don't see it as measurement error (as the electro-boom video claims) nor as discrediting simple applications of KVL.
If you have two resistors with lengths of wire separating them, creating a circle shape, and then you create a magnetic field which induces current in your two resistor loop, then the wires (and perhaps to some extent the resistors too) have been forced to act like inductors. As such, when you add up voltages around the complete circle looking for a zero sum, you can't just measure across the two resistors, but also across the two inductors. The sum of those 4 voltages is zero, just as KVL would predict.
I don't see what all the fuss is about. There's no reason to think the measurements are inaccurate, it's just that not all of the relevant voltages have been measured and included in the calculation. Here's a simple sim with the pulse generator in the center, and then the two resistors and two wires (modeled as inductors) in a circle around the pulse source. As in both videos, the voltages across the two resistors are totally different. However, if you include the two inductor voltages, it all adds up perfectly (notice the yellow-brown line, the sum of all 4 voltages, is perfectly flat!)
View attachment 176568
What about the electrons running back inside the burning building? Their sacrifice should always be remembered.{jumping into this mixer}
Ten electrons are running down a hallway (wire) escaping a burning building (electric pressure). At the end of the hallway are two doors (resistors). One door is stuck half way open, the other stuck a quarter way open. Six (approximately) electrons can squeeze through the half open door, the other four (approximately) squeeze through the door stuck a quarter way open.
Same analogy: 100 mA of current flows down a wire being pushed by electromotive force. The circuit branches off into two resistors. One resistor is 50 ohms, the other 25. (to understand the relationship - the 25 ohm resistor represents the half open door and the 50 ohm resistor is the quarter open door). 66.6 mA will go through the 25 ohm resistor while 33.3 mA go through the other door (ignore the 99% issue, I'm rounding off to a single decimal place).
ONLY if one of those resistors are zero ohms will all the current pass through that resistor. Yes, current will flow through the path of least resistance. But where there is resistance in two paths, they will split up according to their resistances.
They weren't destroyed, they were transformed into another form of energy.What about the electrons running back inside the burning building? Their sacrifice should always be remembered.
Correct, they always remain electrons but they never carried the energy of the circuit even when leaving the 'burning building' and they don't get transformed on return. They just move like the links of a chain on a sprocket.They weren't destroyed, they were transformed into another form of energy.