Can you explain about the inspection? Thanks!!Here is one easy way to compute the resistors. Start by assuming R1 + R2 + R3 = 15K.
By inspection you get R3 = 4.4K, R2 = (5.7-4.4)K, and R3 = 15K - R2 - R3.
Next I open Excel and create an equation to compute the two voltages given the resistor values.
Finally I play with real world resistor values to see how close to the ideal I can get with real parts I can get.
He chose a sum of 15 kΩ so that the current through the string of resistors is 1 mA. That means that the voltage across each resistor will be 1 V per kΩ.Can you explain about the inspection? Thanks!!
If he runs it at 5 V he will need to attentuate all of his signals since his window is from 4.4 V to 5.7 V.Two things I would change.
1) You do not need -15V supply. I would use a single supply circuit.
2) You do not need 15V supply. I would choose a lower supply voltage such as 5V.
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