Resistor Load Bank (RLB)I find the RLB references humorous because RLB is my initials.
Resistor Load Bank (RLB)I find the RLB references humorous because RLB is my initials.
Please tell I am not reading this correctly — that you don’t really think you can keep 5V across a resistive load and vary the current.Like I mentioned, I said I will keep a constant 5V and only vary the current through all that Resistor Load Bank (RLB).
You saw where I questioned that.Please tell I am not reading this correctly — that you don’t really think you can keep 5V across a resistive load and vary the current.
if you folowed me along, youve seen I already did that but in a very special case, when no component in test is connected to the load. When only a wire is connected . This way I could program all those nice values you've seen in the movie, the 1, 10 and 100's.you don’t really think you can keep 5V across a resistive load and vary the current.
So when you replace a wire with a resistor, you expect the voltage and current to remain the same?if you folowed me along, youve seen I already did that but in a very special case, when no component in test is connected to the load. When only a wire is connected .
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But in the moment I connected the component in test, the whole idea crumble because the voltage changed through voltage dividing.
Is not what I expect, is what I observe. It is the same over the 1R shunt, when is in wire mode. But not when I replace the wire with something else, a tr, a diode or another res. It goes into a voltage divider mode. Which it was not very clear with the opamp cct, but it is very clear, right in your face clear, with the Load res bank cct. In this case, this voltage divider that is formed, is an obstacle for what I wanted to obtain.So when you replace a wire with a resistor, you expect the voltage and current to remain the same?