Your Karnaugh map is incomplete.
In the top left corner of each box, include the digits 0-7 to remind you which numeral is being presented.
Then include 0 when needed and X when there is a "don't care" condition.

After you have done that, look at this AAC educational link to learn how to derive the combinational logic from each Karnaugh map.

https://www.allaboutcircuits.com/textbook/digital/chpt-8/logic-simplification-karnaugh-maps/

 

The kmaps in post #20 are correct as far as you went. The truth table doesn't reflect the don't care counts.

Next time, take a screen shot instead of taking a picture. We won't have to deal with the Moire patterns and alignment issues.

 

The kmaps in post #20 are correct as far as you went. The truth table doesn't reflect the don't care counts.
View attachment 324789
Next time, take a screen shot instead of taking a picture. We won't have to deal with the Moire patterns and alignment issues.

K

 

K

I had to use 15 NAND gates when the number 7 had to be decoded (even though it isn't supposed to be applied).

 

I had to use 16 NAND gates when the number 7 had to be decoded (even though it isn't supposed to be applied).

U did using the multisim for number 2-7?
can anybody show me Boolean for abcdefg separately!?

 

U did using the multisim for number 2-7?

I used a different simulator.

can anybody show me Boolean for abcdefg separately!?

That isn't how homework help works. You need to show us your work.

Correct your truth table, transfer data to the kmaps, and write your equations.

 

I used a different simulator.
That isn't how homework help works. You need to show us your work.

Correct your truth table, transfer data to the kmaps, and write your equations.

Relax! If cannot just say nicely!

 

If cannot just say nicely!

I just stated facts. There's nothing "not nice" about that.

However, asking for answers is considered bad form in the Homework Help forum.

 

I just stated facts. There's nothing "not nice" about that.

K

 

What

K

What

I used a different simulator.
That isn't how homework help works. You need to show us your work.

Correct your truth table, transfer data to the kmaps, and write your equations.

My assignment I have to ignore 0 & 1. So it’s my kmap wrong cause I didn’t put logic 1 those that has number 1 in the number 0 & 1

 

My assignment I have to ignore 0 & 1. So it’s my kmap wrong cause I didn’t put logic 1 those that has number 1 in the number 0 & 1

The entries for 0 and 1 are don't cares because you aren't required to decode those counts. Unlike 7 which is an invalid input, but you're required to decode it anyway.

The don't cares let you simplify most of the terms.

 

Okie g

The entries for 0 and 1 are don't cares because you aren't required to decode those counts. Unlike 7 which is an invalid input, but you're required to decode it anyway.

The don't cares let you simplify most of the terms.

Ok give me few moments! I will try to do my Boolean expression and help me check if it’s correct!

 

Is my Boolean expression correct? If not pls help me correct it!

 

It doesn't look like you're using the don't cares correctly and you haven't populated the kmaps correctly. It would be helpful if you drew circles on the map for each term.

 

It doesn't look like you're using the don't cares correctly and you haven't populated the kmaps correctly. It would be helpful if you drew circles on the map for each term.

Ok why not just help me with the letter ‘a’ I will try to figure out the rest

 

Ok why not just help me with the letter ‘a’ I will try to figure out the rest

By using the don't care for count 1, you can make a group of 4 for the blue group.

Even without doing that, your CB'A term could have been CA.

 

View attachment 324798
By using the don't care for count 1, you can make a group of 4 for the blue group.

Why did u put a c at 001?

 

Why did u put a c at 001?

Is not logic 1 for 001

 

View attachment 324798
By using the don't care for count 1, you can make a group of 4 for the blue group.

Even without doing that, your CB'A term could have been CA.

Ahhhh this is so difficult I am not even sure!

 

1. 
   

2. View attachment 324798
   By using the don't care for count 1, you can make a group of 4 for the blue group.
   
   Even without doing that, your CB'A term could have been CA.

   So that means since my assignment is don care 0&1 that means I have to put a cross accordingly even though the logic is 0 at output?