Urgent(capacitor with dependent source)

Thread Starter

Furki

Joined Mar 1, 2009
10
Hello friends,

The voltage source V2 is a unit step source which gives 100V after t = 0.
I want to know the equation of the instantaneous voltage across the capacitor. voltage becomes 500V(approx) after 60-70 seconds.
Ive tried to derive it but I dont think its correct.
Heres the equation:
vc = 100/((1/1 - e^t/RC) - 0.8)

vc is the voltage across capacitor and it controls the current through the independent source. Heres the schematic.
http://img12.imageshack.us/img12/8358/uploada.jpg

Any help will be much appreciated.
thanks.
 

t_n_k

Joined Mar 6, 2009
5,455
If V1 is 0V - not sure why it's in the circuit if the case - then I have ...

Vc = 500(1-exp(-71.429*t)) which partially agrees with your expected result.

I would expect the value to be 500V after 60-70 milliseconds.
 

Thread Starter

Furki

Joined Mar 1, 2009
10
Thank you for your reply,
Yes, V1 is 0 volts. It is there because the old version of ICAP doesn't allow you to measure current without it. My equation only works when t is large. for small values of t like 5ms or 10ms, it fails.
 

Thread Starter

Furki

Joined Mar 1, 2009
10
It would be really great if you tell me how to get to that equation from superposition or whatever method you used, especially the "-71.429" part. pleeeeeease!!!! :(
 

Ratch

Joined Mar 20, 2007
1,070
Furki,

Let me get this straight. According to the schematic, you have the capacitor physically grounded on one end, and virtually grounded at the other end by connecting it to the input terminals of a op amp? Does that make sense?

Ratch
 

Thread Starter

Furki

Joined Mar 1, 2009
10
Ratch,

Yes, the control port of the dependent source is connected to the capacitor so that the capacitor voltage(Vc) controls the current of the dependent source(I).
I = 0.02*Vc

Capacitor is also connected to V2. (forget the V1 source, its zero volts)
V2 = 100V
 
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