The same concept applies to the FET, except instead of a varying base current you will have a varying gate to source voltage. Is the graph you put in your original post a depletion mode JFET? That would account for the negative Vgs.Hello i have LNA with 50 ohm, ports on both sides.
what is my RL? 50ohms?
how do i know what Q operating point to take from the multiple plots?
Thanks.
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You choose the point on the load line that allows for an equal swing of the input waveform in such a way that the device does not go into "pinchoff" or the "ohmic region". Doing either of those things will result in distortion, which you do not want in a linear amplifier. If you choose the Q-point at M1 in the original diagram your input can swing ±350 mV without going into either region.Hello PapaBravo, how do i choose the point location on the load line?
Thanks.
by Jake Hertz
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