I don't have equipment, no technical knowledge anymore after severe traffic accident some years ago. I will attempt to be clear, and step by step.

I see that solid 18 gauge, 5 foot length "X" of copper straight wire has inductance of ~ 2410 nh. If I add another 5 foot length of 18 gauge solid wire "Y" for return path, we have an additional inductance of 2410 nh.

Next, I can go two ways. The first is to twist the two wires, "X" and "Y" together to reduce the inductance. I know insulation thickness, turns per inch will play a role in inductance cancellation due to centers distance from each other, but I don't have an insulation thickness value yet.

Next, another way is to keep the two wires, "X" and "Y" very separate and simply parallel additional 18 gauge wires to "X" and to "Y", to reduce the inductance of "X" and of "Y". Say 5 or 10 wires in parallel. I figured that 10 wires in parallel for each of "X" and "Y" would reduce the inductance to approximately 241 nh times 2 ("X" and "Y").

My question is can twisting the single "X" and "Y" wires together really reduce the inductance as much as paralleling 5 or 10 straight "X" wires and paralleling 5 or 10 straight "Y" wires? (I would also separate the "X" parallel wires and "Y:" as well.)

I appreciate your help and time very much.

steve sammet