The transistor will be dissipating around 100W. You need a huge heat sink.do i need a large heat sink?
To your question. There are exactly three methods of removing heat from a system and they are:so how to solve this dilemma? 50 w and small heat sink
i get 27.2 only when the opamp power is 32 v and this isn't available. when i reduce supply to 12 v which is available i get emitter voltage 9.5v. so (30-9.5)*4=80w which isn't manageable.Now, change the collector voltage to 30V and we get (30-27.2) * 4 = 11W, which is manageable.
I need something simple and easy at low cost. what is the maximum heat that can be dissipated with small heatsink. i can connect two parallel loads with transistors if we ran out of solutionswould you like spend BOATLOADS of money on?
no it is not misleading. i want 4 A to get it i had to increase the opamp power supply to 30 v.So your 6R8 resistor and the 50V input is just there to mislead us, I guess.
I guess you don't really understand the drift here. Your requirements are in severe conflict. It is doubtful that you can accomplish your goal, especially since we have no idea what done looks like.I need something simple and easy at low cost. what is the maximum heat that can be dissipated with small heatsink. i can connect two parallel loads with transistors if we ran out of solutions
by Aaron Carman
by Duane Benson
by Duane Benson