Okay,i understand.Thanks again for this clarificationNo, at least that is not what I intended to imply. The connecting leads do not get hot enough to melt solder, I have no idea how hot the part that burns up gets. But the tubing used for that purpose does not catch fire, so it must be adequate for the temperature. And as long as the protective fuse opens and cuts off the power, the length of time that the varistor is getting hot will be limited, and so the heat will not spread a lot. That is why a fuse is used. It limits the total amount of heat energy when the fails.