The internal resistance of battery and dc generator - help, I'm stuck.

Thread Starter

Christine Grech

Joined May 31, 2015
6
I need to solve this, but I need help...

'A battery having an emf of 105V and an internal resistance of 1 Ohm is connected in parallel with a d.c generator of emf 110V and internal resistance of 0.5 Ohm to supply a load having a resistance of 8 Ohms. Calculate: a) the currents in the battery, the generator and the load; b) the potential difference across the load.'

For question number a), is it right if I use 'V=Emf-Ir' please?
 

LDC3

Joined Apr 27, 2013
924
If both positive terminals of the voltage sources are connected together, than that equation only tells you the voltage across the battery, not the voltage across the load.
 

bertus

Joined Apr 5, 2008
22,277
Hello,

As asked, post your schematic here, so we can have a look you made a correct one.
You can do this using the "Upload a File" button below the reply box.

Bertus
 

ericgibbs

Joined Jan 29, 2010
18,849
Hi CG,
Is this your diagram.?

EMF is the open circuit voltage, so the V will be EMF - Iamp

But more maths are required to solve the problem.
E
 

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JoeJester

Joined Apr 26, 2005
4,390
I found it easier to use the Norton equivalent of the two sources and then find the equivalent resistance of the internals and the load.
 
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