I asked my teacher, and they said they checked and insist there is absolutely nothing wrong with the solution. Can someone point out the mistake I am making?
The second set of equations in particular, make no sense. Relating to V2.
How do you get V2/2=6+(4ixV2)/8 from that second diagram?
In that second diagram, the solution is equating Ix with V2/2. Is that correct?
Then from that equation, you get v2/2 = 6 + (2v2 – v2)/8 which apparently leads to v2 = 16 (according to the solution). Except that it doesn't. It leads to V2 = 16.
Then it says that ix=Vx/2. I don't understand where that came from. If I assume ground is to the right of the 4ix voltage source, the equation I come up with for ix is ix=(4ix+Vx)/2 > ix = Vx/2
If I disregard the solution, and make my own equations, my final answer is always Ix=13.333A, instead of 13.333A.
Can someone tell me what I'm doing wrong?
First set of equations:
V1/8 + (V1(4ix))/2 =4
ix=(v1+4ix)/2 > ix=v1/2
V1 = (32/3)
Second set of equations:
(4ix+V2)/2 = 6 + (4ix4ixV2)/8
ix = (v2+4ix)/2 > ix= v2/2
V2=16

Vx = V1+V2 = 26.67...V
ix=(4ix+Vx)/2
ix=Vx/2=(26.67)/2=13.33A
The second set of equations in particular, make no sense. Relating to V2.
How do you get V2/2=6+(4ixV2)/8 from that second diagram?
In that second diagram, the solution is equating Ix with V2/2. Is that correct?
Then from that equation, you get v2/2 = 6 + (2v2 – v2)/8 which apparently leads to v2 = 16 (according to the solution). Except that it doesn't. It leads to V2 = 16.
Then it says that ix=Vx/2. I don't understand where that came from. If I assume ground is to the right of the 4ix voltage source, the equation I come up with for ix is ix=(4ix+Vx)/2 > ix = Vx/2
If I disregard the solution, and make my own equations, my final answer is always Ix=13.333A, instead of 13.333A.
Can someone tell me what I'm doing wrong?
First set of equations:
V1/8 + (V1(4ix))/2 =4
ix=(v1+4ix)/2 > ix=v1/2
V1 = (32/3)
Second set of equations:
(4ix+V2)/2 = 6 + (4ix4ixV2)/8
ix = (v2+4ix)/2 > ix= v2/2
V2=16

Vx = V1+V2 = 26.67...V
ix=(4ix+Vx)/2
ix=Vx/2=(26.67)/2=13.33A
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