Hey. I am studying electrical engineering.
I set a function generator to output a square wave, with a peak to peak amplitude of 1.6V, a frequency of 1600Hz, a duty cycle of 10% and an offset of 1V.
I connected my function generator to an oscilloscope. In channel 1, the yellow one, the coupling is AC and in channel 2, the blue one, the coupling is DC. Here is a photo
I also connected the function generator to a voltmeter, and in DC mode the value was around 0.500V.
Then I set the duty cycle of the wave to 50% and the DC value measured in the oscilloscope raised to around 1V.
Can someone explain how the duty cycle affects the DC component of the signal? Why does the duty cycle affects the offset? Shouldn't the offset always be 1V?
Thanks
I set a function generator to output a square wave, with a peak to peak amplitude of 1.6V, a frequency of 1600Hz, a duty cycle of 10% and an offset of 1V.
I connected my function generator to an oscilloscope. In channel 1, the yellow one, the coupling is AC and in channel 2, the blue one, the coupling is DC. Here is a photo
I also connected the function generator to a voltmeter, and in DC mode the value was around 0.500V.
Then I set the duty cycle of the wave to 50% and the DC value measured in the oscilloscope raised to around 1V.
Can someone explain how the duty cycle affects the DC component of the signal? Why does the duty cycle affects the offset? Shouldn't the offset always be 1V?
Thanks