Don't you have to have the convolution before you can get the Fourier Transform?I think that the exercise is asking you a) the Fourier transform and b) the convolution of the two signals.
Do you know how to proceed ?
Do you know of a way to get the Fourier Transform before you get the convolution?Fourier transform
Ahhh....I thought I remembered a theorem to that effect. So you can compute the Fourier transforms of x(t), and h(t). Multiply them together to get Y(iω), and finally take the inverse Fourier Transform to get y(t). Did I get that right? Now the TS/OP really really has to do something so we can proceed. This is enough now with the hints.I don't have his paper down on my table, but a) is the Fourier Transform and b) should (or could) be the convolution.
Also:
X(iw)H(iw) = x(t) * h(t)
I agree!papabravo said:Now the TS/OP really really has to do something so we can proceed. This is enough now with the hints.
Yeah, remember, convolution in time domain (which is a pain in the butt) is simple multiplication in the frequency domain.Ahhh....I thought I remembered a theorem to that effect. So you can compute the Fourier transforms of x(t), and h(t). Multiply them together to get Y(iω), and finally take the inverse Fourier Transform to get y(t). Did I get that right? Now the TS/OP really really has to do something so we can proceed. This is enough now with the hints.
thumb2, I think the OP is supposed to use transformation identities, I remember my Signal and Systems textbook had a whole table where they would have time domain representation of a signal on one side and corresponding frequency domain representation on the other side. There was something like 8 or 10 entries in that table, impulse, step, ramp, sine and a few others. This way students can quickly work out their time domain signal into frequency domain signal, without doing the whole Fourier Transform.I don't have his paper down on my table, but a) is the Fourier Transform and b) should (or could) be the convolution.
Also:
X(iw)H(iw) = x(t) * h(t)
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