So according to Ohm's law, the secondary current of a transformer can be found from dividing the secondary voltage by the resistance of the load (Is = Es/Rl). According to this formula, as the secondary voltage decreases, the secondary current should also decrease (assuming that resistance stays constant.)
Well today in class I learned that a short in the secondary of a transformer causes voltage to go down, since a short basically lowers the number of windings of the coil. But according to my reading a short in the secondary of a transformer causes current to increase. This also makes sense, since shorts normally increase current.
So the math doesn't seem to add up. If a secondary short in a transformer causes voltage to decrease and current to increase, then how can Is=Es/Rl? I know a short will decrease the resistance of the transformer itself, but the resistance of the transformer isn't that significant is it?
Well today in class I learned that a short in the secondary of a transformer causes voltage to go down, since a short basically lowers the number of windings of the coil. But according to my reading a short in the secondary of a transformer causes current to increase. This also makes sense, since shorts normally increase current.
So the math doesn't seem to add up. If a secondary short in a transformer causes voltage to decrease and current to increase, then how can Is=Es/Rl? I know a short will decrease the resistance of the transformer itself, but the resistance of the transformer isn't that significant is it?