Hello

Could somebody suggest how could the output of the peak detector that has ripples be removed. I mean I want to remove the ripples ...does the ripples appear at 433MHz from the output of peak detector.

please suggest.
thanks

 

please help to the above question. if any more data is needed please post back.
thanks

 

please help to the above question. if any more data is needed please post back.
thanks

Calculate R*C to be 10 times greater than 1/f

where R=the resistor in parallel with the capacitor C
C=the capacitor
f=your frequency

Are you sure you have 433 MHz frequency?
What is your circuit built of?

 

You can't remove the ripple entirely, but you can also use this formula:
C = Iload / (Vripple * f) for an approximation.

mik3's formula is correct considering 10% ripple (Vripple / Vtot = 0.1).