R9 sets the threshold at which Q1 begins to turn ON.circuit is useless and makes no sense. plus it is drawn wery awkward.. R3,R4 are in parallel with R5 but places far away, with additional line crossings. placing three equal low value resustoprs in parallel would suggest there is high current through them, but it cannot be - at lest not from what you have drawn. because there are exactly three paths leading to this resistor back:
Q1 converts the slow RC voltage ramp into a sharper transistor switching waveform.
R2 ensures Q1 switches smoothly instead of snapping abruptly.
R3/R4 ensure the LED receives safe, controlled current.
Current limiting is problem here ?a) R7 which is way to high and would limit such current.
Q6 is the master controller that decides when the LED driver section turns ON or OFF. If we improve the Q2 connection it will be better.b) Q5 which is also a dead end - C1 can be charged by currents through R9 and R2. both of which are way too high to make any difference for three 5.1 Ohm resistors in parallel.
Q1 emitter is connected to Q2 collector, and its base is in GND, it’s a problem.c) Q2 which is completely dead - no current flows through here.
Can we change here likewise,
- Q1 emitter → small resistor → GND
- Q1 base → bias/timing network (via R9, etc.)
- Q1 collector → R7 → Q2 base
- Q2 emitter → small resistor → GND
- Q2 collector → R1 → Q6 base
It can improve, Q1 responds to the timing voltage. Q2 amplifies Q1’s output, Q6 gets a strong, well‑defined drive.
Leve D1 at this moment.next, D1 is a dead short for reverse polarity. so connecting AC to J1 would blow it up.
SW2 and everything right of it does nothing. when SW2 is in position:
Is its same now in post #5 ?1. current through R8 has nowhere to go. on one side is insulator (gate of Q5), and the other is through Q3 with nothing to drive its base.
Load is not mentioned here, it is a three‑transistor amplifier chain (Q1 → Q2 → Q6) that takes the slow timing signal from the RC network and turns it into a strong switching signal that controls the LED driver.2. not connected to enything so - nothing.
3. R11 conly connect to C2. 1uF make no difference anyway since it would be in parallel with C3 and C4 which are 2000x larger capacitance.
finally there is no load. for any circuit to do something, there meed to be some sort of load or "business end". this circuil lacks scuh thing. if J2 is meant as place to connect load (like 5W LED), then i am sorry to dissapoint you, R7 is a major problem to getting those 5W out.
