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RCR in series with switch

S

Thread Starter

sampan511

Joined Feb 17, 2013
1
Hi,

Can anyone explain the following circuit, when switch is closed at t0+, why the voltage at V(y) drops to 3.33V?

I can only explain the values from the voltage divider equation.
V(x) = 10V * (R4)/(R3+R4)
= 10V * 1 / 3
= 3.33V
V(z) = -10V * (R3)/(R3+R4)
= -6.66V

But why?
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upload_2015-4-9_12-39-7.png
 
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